What happens if you try to dereference a value that is not a hard reference? The value is then treated as a symbolic reference . That is, the reference (which still has a scalar value) is interpreted as a string. That string is taken to be the name of a variable, rather than a direct link to a (possibly anonymous) thingy.
Here is how it works:
$name = "bam"; $$name = 1; # Sets $bam ${$name} = 2; # Sets $bam ${$name x 2} = 3; # Sets $bambam $name->[0] = 4; # Sets $bam[0] @$name = (); # Clears @bam &$name(); # Calls &bam() (as in prior versions of Perl) $pkg = "THAT"; # (Don't use "package" or "pack"!) ${"${$pkg}::$name"} = 5; # Sets $THAT::bam without eval
This is very powerful, and slightly dangerous, in that it's possible to intend (with the utmost sincerity) to use a hard reference, and accidentally use a symbolic reference instead. To protect against that, you can say:
use strict 'refs';
and then only hard references will be allowed for the rest of the enclosing block. An inner block may countermand that decree with:
no strict 'refs';
It is important to note the difference between the following two lines of code:
${identifier}; # same as $identifier ${"identifier"}; # also $identifier, but treated as symbolic reference
Because the second form is treated as a symbolic reference, it will generate an error under
use strict 'refs'
.
Only package variables are visible to symbolic references. Lexical variables (declared with my ) aren't in a package symbol table, and thus are invisible to this mechanism. For example:
local $value = "10"; { my $value = "20"; print ${"value"}; }
This will print "
10
", not "
20
". Remember that
local
affects package variables, which are all global to the package.